Address-of Operator

suggest change

For any object (i.e, variable, array, union, struct, pointer or function) the unary address operator can be used to access the address of that object.

Suppose that

int i = 1;              
int *p = NULL;

So then a statement p = &i;, copies the address of the variable i to the pointer p.

It’s expressed as p points to i.

printf("%d\n", *p); prints 1, which is the value of i.

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