Iterating Over the Characters in a String

suggest change

If we know the length of the string, we can use a for loop to iterate over its characters:

char * string = "hello world"; /* This 11 chars long, excluding the 0-terminator. */
size_t i = 0;
for (; i < 11; i++) {
    printf("%c\n", string[i]);    /* Print each character of the string. */
}

Alternatively, we can use the standard function strlen() to get the length of a string if we don’t know what the string is:

size_t length = strlen(string);
size_t i = 0; 
for (; i < length; i++) {
    printf("%c\n", string[i]);    /* Print each character of the string. */
}

Finally, we can take advantage of the fact that strings in C are guaranteed to be null-terminated (which we already did when passing it to strlen() in the previous example ;-)). We can iterate over the array regardless of its size and stop iterating once we reach a null-character:

size_t i = 0;
while (string[i] != '\0') {       /* Stop looping when we reach the null-character. */
    printf("%c\n", string[i]);    /* Print each character of the string. */
    i++;
}

Feedback about page:

Feedback:
Optional: your email if you want me to get back to you:



Table Of Contents