Changing the nth bit to x
suggest changeC-style bit-manipulation
// Bit n will be set if x is 1 and cleared if x is 0.
number ^= (-x ^ number) & (1LL << n);
Using std::bitset
set(n,val)
- sets bit n
to the value val
.
std::bitset<5> num(std::string("00100"));
num.set(0,true); // num is now 00101
num.set(2,false); // num is now 00001
Found a mistake? Have a question or improvement idea?
Let me know.
Table Of Contents