Return Type in Function Overloading
suggest changeNote that you cannot overload a function based on its return type. For example:
// WRONG CODE
std::string getValue()
{
return "hello";
}
int getValue()
{
return 0;
}
int x = getValue();
This will cause a compilation error as the compiler will not be able to work out which version of getValue
to call, even though the return type is assigned to an int
.
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