std find

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template <class InputIterator, class T>
InputIterator find (InputIterator first, InputIterator last, const T& val);

Effects

Finds the first occurrence of val within the range [first, last)

Parameters

first => iterator pointing to the beginning of the range last => iterator pointing to the end of the range val => The value to find within the range

Return

An iterator that points to the first element within the range that is equal(==) to val, the iterator points to last if val is not found.

Example

#include <vector>
#include <algorithm>
#include <iostream>

using namespace std;

int main(int argc, const char * argv[]) {

  //create a vector
  vector<int> intVec {4, 6, 8, 9, 10, 30, 55,100, 45, 2, 4, 7, 9, 43, 48};

  //define iterators
  vector<int>::iterator  itr_9; 
  vector<int>::iterator  itr_43; 
  vector<int>::iterator  itr_50; 

  //calling find
  itr_9 = find(intVec.begin(), intVec.end(), 9); //occurs twice
  itr_43 = find(intVec.begin(), intVec.end(), 43); //occurs once

  //a value not in the vector
  itr_50 = find(intVec.begin(), intVec.end(), 50); //does not occur

cout << "first occurence of: " << *itr_9 << endl;
cout << "only occurence of: " << *itr_43 << Lendl;

/*
  let's prove that itr_9 is pointing to the first occurence
  of 9 by looking at the element after 9, which should be 10 
  not 43
*/
cout << "element after first 9: " << *(itr_9 + 1) << ends;

/*
  to avoid dereferencing intVec.end(), lets look at the 
  element right before the end
*/
cout << "last element: " << *(itr_50 - 1) << endl;

return 0;
}

Output

first occurence of: 9
only occurence of: 43
element after first 9: 10
last element: 48

Found a mistake? Have a question or improvement idea? Let me know.

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