Using a sorted vector for fast element lookup

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The <algorithm> header provides a number of useful functions for working with sorted vectors.

An important prerequisite for working with sorted vectors is that the stored values are comparable with \<.

An unsorted vector can be sorted by using the function std::sort():

std::vector<int> v;
// add some code here to fill v with some elements
std::sort(v.begin(), v.end());

Sorted vectors allow efficient element lookup using the function std::lower_bound(). Unlike std::find(), this performs an efficient binary search on the vector. The downside is that it only gives valid results for sorted input ranges:

// search the vector for the first element with value 42
std::vector<int>::iterator it = std::lower_bound(v.begin(), v.end(), 42);
if (it != v.end() && *it == 42) {
    // we found the element!

Note: If the requested value is not part of the vector, std::lower_bound() will return an iterator to the first element that is greater than the requested value. This behavior allows us to insert a new element at its right place in an already sorted vector:

int const new_element = 33;
v.insert(std::lower_bound(v.begin(), v.end(), new_element), new_element);

If you need to insert a lot of elements at once, it might be more efficient to call push_back() for all them first and then call std::sort() once all elements have been inserted. In this case, the increased cost of the sorting can pay off against the reduced cost of inserting new elements at the end of the vector and not in the middle.

If your vector contains multiple elements of the same value, std::lower_bound() will try to return an iterator to the first element of the searched value. However, if you need to insert a new element after the last element of the searched value, you should use the function std::upper_bound() as this will cause less shifting around of elements:

v.insert(std::upper_bound(v.begin(), v.end(), new_element), new_element);

If you need both the upper bound and the lower bound iterators, you can use the function std::equal_range() to retrieve both of them efficiently with one call:

          std::vector<int>::iterator> rg = std::equal_range(v.begin(), v.end(), 42);
std::vector<int>::iterator lower_bound = rg.first;
std::vector<int>::iterator upper_bound = rg.second;

In order to test whether an element exists in a sorted vector (although not specific to vectors), you can use the function std::binary_search():

bool exists = std::binary_search(v.begin(), v.end(), value_to_find);

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