Creating an array of sequential numbers

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LINQ provides a method that makes it easy to create a collection filled with sequential numbers. For example, you can declare an array which contains the integers between 1 and 100.

The Enumerable.Range method allows us to create sequence of integer numbers from a specified start position and a number of elements.

The method takes two arguments: the starting value and the number of elements to generate.

Enumerable.Range(int start,int count)

Note that count cannot be negative.


int[] sequence = Enumerable.Range(1, 100).ToArray();

This will generate an array containing the numbers 1 through 100 ([1, 2, 3, ..., 98, 99, 100]).

Because the Range method returns an IEnumerable<int>, we can use other LINQ methods on it:

int[] squares = Enumerable.Range(2, 10).Select(x => x * x).ToArray();

This will generate an array that contains 10 integer squares starting at 4: [4, 9, 16, ..., 100, 121].

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