Filtering Object Arrays

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The filter() method accepts a test function, and returns a new array containing only the elements of the original array that pass the test provided.

// Suppose we want to get all odd number in an array:
var numbers = [5, 32, 43, 4];

var odd = numbers.filter(function(n) {
  return n % 2 !== 0;
});

let odd = numbers.filter(n => n % 2 !== 0); // can be shortened to (n => n % 2)

odd would contain the following array: [5, 43].

It also works on an array of objects:

var people = [{
  id: 1,
  name: "John",
  age: 28
}, {
  id: 2,
  name: "Jane",
  age: 31
}, {
  id: 3,
  name: "Peter",
  age: 55
}];

var young = people.filter(function(person) {
  return person.age < 35;
});

let young = people.filter(person => person.age < 35);

young would contain the following array:

[{
  id: 1,
  name: "John",
  age: 28
}, {
  id: 2,
  name: "Jane",
  age: 31
}]

You can search in the whole array for a value like this:

var young = people.filter((obj) => {
  var flag = false;
  Object.values(obj).forEach((val) => {
    if(String(val).indexOf("J") > -1) {
      flag = true;
      return;
    }    
  });
  if(flag) return obj;
});

This returns:

[{
  id: 1,
  name: "John",
  age: 28
},{
  id: 2,
  name: "Jane",
  age: 31
}]

Found a mistake? Have a question or improvement idea? Let me know.

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