Defining a function with multiple arguments

One can give a function as many arguments as one wants, the only fixed rules are that each argument name must be unique and that optional arguments must be after the not-optional ones:

def func(value1, value2, optionalvalue=10):
    return '{0} {1} {2}'.format(value1, value2, optionalvalue1)

When calling the function you can either give each keyword without the name but then the order matters:

print(func(1, 'a', 100))
# Out: 1 a 100

print(func('abc', 14))
# abc 14 10

Or combine giving the arguments with name and without. Then the ones with name must follow those without but the order of the ones with name doesn’t matter:

print(func('This', optionalvalue='StackOverflow Documentation', value2='is'))
# Out: This is StackOverflow Documentation